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# skbio.tree.TreeNode.is_root

`TreeNode.``is_root`()

  Returns True if the current is a root, i.e. has no parent.

  State: Experimental as of 0.4.0.

  Returns: | True if the node is the root
  Return type: | bool

  See also

  `is_tip()`, `has_children()`

  Examples

      >>> from skbio import TreeNode
      >>> tree = TreeNode.read(["((a,b)c);"])
      >>> print(tree.is_root())
      True
      >>> print(tree.find('a').is_root())
      False