# 7.30 Nozzle Sizing Calculations

## Objective: Size a long-radius venturi nozzle flow meter

A system is designed with a flow rate of 225 gpm of water at 60 F flowing through 6” schedule 40 pipe. A long-radius nozzle flow has been requested. A measured head loss of 4 feet is the design measurement, with 1D upstream and 1/2D downstream taps.

Find the required diameter of the nozzle.

    [1]:

    from fluids.units import *
    from math import pi

    mu = 1.1*u.cP
    rho = 62.364*u.lb/u.ft**3

    NPS, Di, Do, t = nearest_pipe(NPS=6, schedule='40')
    A = 0.25*pi*Di*Di

    dP = 4*u.feet_H2O

    P1 = 10*u.bar # assumed, not very important
    P2 = P1 - dP
    k = 1.3 # not important

    Q = 225*u.gal/u.min
    m = Q*rho

    [2]:

    Do = differential_pressure_meter_solver(D=Di, rho=rho, mu=mu, k=k, P1=P1, P2=P2,
                                       m=m, meter_type='long radius nozzle',
                                       taps='D')
    print('Nozzle diameter found to be %s.' %(Do.to(u.inch)))

    Nozzle diameter found to be 2.405956560384601 inch.

The solution given in Crane is 2.40 inches after two iterations and has an error of 0.4 gpm, whereas the answer above has almost zero theoretical error.

# 7.31 NPRD Calculations

The Non-recoverable pressure drop (NRPD) is the permanent pressure drop associated with the flow through the measurement device. Find the NPRD for example 7.30.

    [3]:

    C, epsilon = differential_pressure_meter_C_epsilon(D=Di, D2=Do, m=m, P1=P1, P2=P2, rho=rho, mu=mu, k=k,
                                              meter_type='long radius nozzle')
    C

    [3]:

0.983900143257091 dimensionless

    [4]:

    dP = differential_pressure_meter_dP(D=Di, D2=Do, P1=P1, P2=P2, C=C,
                                       meter_type='long radius nozzle')

    dP.to(u.psi)

    [4]:

1.2691031737597416 pound_force_per_square_inch

The solution given in Crane is 1.272 psi.