# Variables

This example shows how to find variables and find information about them.

Let’s consider the following c++ file:

    namespace ns{
        int a = 1;
        int b = 2;
        double c = 3.0;
    }

The following code can be use to find the variable named “c” using different strategies, and to print information about it:

    from pygccxml import utils
    from pygccxml import declarations
    from pygccxml import parser

    # Find out the c++ parser
    generator_path, generator_name = utils.find_xml_generator()

    # Configure the xml generator
    xml_generator_config = parser.xml_generator_configuration_t(
        xml_generator_path=generator_path,
        xml_generator=generator_name)

    # The c++ file we want to parse
    filename = "example.hpp"

    decls = parser.parse([filename], xml_generator_config)
    global_namespace = declarations.get_global_namespace(decls)
    ns = global_namespace.namespace("ns")

    # The variables() method will return a list of variables.
    # We know that the c variable is the third one in the list:
    c = ns.variables()[2]
    print("My name is: " + c.name)
    print("My type is: " + str(c.decl_type))
    print("My value is: " + c.value)

    # Of course you can also loop over the list and look for the right name
    for var in ns.variables():
        if var.name == "c":
            print("My name is: " + var.name)
            print("My type is: " + str(var.decl_type))
            print("My value is: " + var.value)

    # One way to get a variable is to use the variable() method and
    # a lambda function. This is the most flexible way as you can implement
    # your own lambda function to filter out variables following your
    # specific criteria.
    c = ns.variable(lambda v: v.name == "c")
    print("My name is: " + c.name)
    print("My type is: " + str(c.decl_type))
    print("My value is: " + c.value)