# Method Stdio.File()->create()

Method create

  `Stdio.File Stdio.File()`
  `Stdio.File Stdio.File(`string` `filename`)`
  `Stdio.File Stdio.File(`string` `filename`, `string` `mode`)`
  `Stdio.File Stdio.File(`string` `filename`, `string` `mode`, `int` `mask`)`
  `Stdio.File Stdio.File(`string` `descriptorname`)`
  `Stdio.File Stdio.File(`int` `fd`)`
  `Stdio.File Stdio.File(`int` `fd`, `string` `mode`)`

Description

  There are four basic ways to create a Stdio.File object. The first is calling it without any arguments, in which case the you'd have to call open(), connect() or some other method which connects the File object with a stream.

  The second way is calling it with a `filename` and open `mode`. This is the same thing as cloning and then calling open(), except shorter and faster.

  The third way is to call it with `descriptorname` of `"stdin"`, `"stdout"` or `"stderr"`. This will open the specified standard stream.

  For the advanced users, you can use the file descriptors of the systems (note: emulated by pike on some systems - like NT). This is only useful for streaming purposes on unix systems. This is not recommended at all if you don't know what you're into. Default `mode` for this is `"rw"`.

Note

  Open mode will be filtered through the system UMASK. You might need to use `chmod()` later.

See also

  open(), connect(), Stdio.FILE,