# Assignment operators

From cppreference.com
< cpp‎ | language

Assignment operators modify the value of the object.

Operator name | Syntax | Over​load​able | Prototype examples (for class T)
--- | --- | --- | ---
Inside class definition | Outside class definition
simple assignment | `a = b` | Yes | T& T::operator =(const T2& b); | N/A
addition assignment | `a += b` | Yes | T& T::operator +=(const T2& b); | T& operator +=(T& a, const T2& b);
subtraction assignment | `a -= b` | Yes | T& T::operator -=(const T2& b); | T& operator -=(T& a, const T2& b);
multiplication assignment | `a *= b` | Yes | T& T::operator *=(const T2& b); | T& operator *=(T& a, const T2& b);
division assignment | `a /= b` | Yes | T& T::operator /=(const T2& b); | T& operator /=(T& a, const T2& b);
modulo assignment | `a %= b` | Yes | T& T::operator %=(const T2& b); | T& operator %=(T& a, const T2& b);
bitwise AND assignment | `a &= b` | Yes | T& T::operator &=(const T2& b); | T& operator &=(T& a, const T2& b);
bitwise OR assignment | `a |= b` | Yes | T& T::operator |=(const T2& b); | T& operator |=(T& a, const T2& b);
bitwise XOR assignment | `a ^= b` | Yes | T& T::operator ^=(const T2& b); | T& operator ^=(T& a, const T2& b);
bitwise left shift assignment | `a <<= b` | Yes | T& T::operator <<=(const T2& b); | T& operator <<=(T& a, const T2& b);
bitwise right shift assignment | `a >>= b` | Yes | T& T::operator >>=(const T2& b); | T& operator >>=(T& a, const T2& b);

  Notes

- All built-in assignment operators return *this, and most user-defined overloads also return *this so that the user-defined operators can be used in the same manner as the built-ins. However, in a user-defined operator overload, any type can be used as return type (including void).
- `T2` can be any type including `T`

### Explanation

copy assignment operator replaces the contents of the object `a` with a copy of the contents of `b` (`b` is not modified). For class types, this is a special member function, described in copy assignment operator.

move assignment operator replaces the contents of the object `a` with the contents of `b`, avoiding copying if possible (`b` may be modified). For class types, this is a special member function, described in move assignment operator. (since C++11)

For non-class types, copy and move assignment are indistinguishable and are referred to as direct assignment.

compound assignment operators replace the contents of the object `a` with the result of a binary operation between the previous value of `a` and the value of `b`.

#### Builtin direct assignment

For every type `T`, the following function signatures participate in overload resolution:

T*& operator=(T*&, T*); |  |
T*volatile & operator=(T*volatile &, T*); |  |

For every enumeration or pointer to member type `T`, optionally volatile-qualified, the following function signature participates in overload resolution:

T& operator=(T&, T ); |  |

For every pair A1 and A2, where A1 is an arithmetic type (optionally volatile-qualified) and A2 is a promoted arithmetic type, the following function signature participates in overload resolution:

A1& operator=(A1&, A2); |  |

For expressions E1 of any scalar type `T`, the following additional forms of the builtin assignment expression are allowed:

E1 = {} |  | (since C++11)
E1 = {E2} |  | (since C++11)

Note: the above includes all non-class types except reference types, array types, function types, and the type void, which are not directly assignable.

The direct assignment operator expects a modifiable lvalue as its left operand and an rvalue expression or a braced-init-list (since C++11) as its right operand, and returns an lvalue identifying the left operand after modification.

For non-class types, the right operand is first implicitly converted to the cv-unqualified type of the left operand, and then its value is copied into the object identified by left operand.

When the left operand has reference type, the assignment operator modifies the referred-to object.

If the left and the right operands identify overlapping objects, the behavior is undefined (unless the overlap is exact and the type is the same)

If the right operand is a braced-init-list

- if the expression `E1` has scalar type,

  - the expression E1 = {} is equivalent to E1 = T{}, where `T` is the type of `E1`.
  - the expression E1 = {E2} is equivalent to E1 = T{E2}, where `T` is the type of `E1`.

- if the expression `E1` has class type, the syntax E1 = {args...} generates a call to the assignment operator with the braced-init-list as the argument, which then selects the appropriate assignment operator following the rules of overload resolution. Note that, if a non-template assignment operator from some non-class type is available, it is preferred over the copy/move assignment in `E1 = {}` because `{}` to non-class is an identity conversion, which outranks the user-defined conversion from `{}` to a class type.

(since C++11)

### Example

Run this code

    #include <iostream>
    int main()
    {
        int n = 0;  // not an assignment
        n = 1;      // direct assignment
        std::cout << n << ' ';
        n = {};     // zero-initialization, then assignment
        std::cout << n << ' ';
        n = 'a';    // integral promotion, then assignment
        std::cout << n << ' ';
        n = {'b'};   // explicit cast, then assignment
        std::cout << n << ' ';
        n = 1.0;    // floating-point conversion, then assignment
        std::cout << n << ' ';
    //    n = {1.0}; // compiler error (narrowing conversion)

        int& r = n;  // not an assignment
        int* p;

        r = 2;       // assignment through reference
        std::cout << n << '\n';
        p = &n;      // direct assignment
        p = nullptr; // null-pointer conversion, then assignment

        struct {int a; std::string s;} obj;
        obj = {1, "abc"}; // assignment from a braced-init-list
        std::cout << obj.a << ':' << obj.s << '\n';
    }

Output:

    1 0 97 98 1 2
    1:abc

#### Builtin compound assignment

For every pair A1 and A2, where A1 is an arithmetic type (optionally volatile-qualified) and A2 is a promoted arithmetic type, the following function signatures participate in overload resolution:

A1& operator*=(A1&, A2); |  |
A1& operator/=(A1&, A2); |  |
A1& operator+=(A1&, A2); |  |
A1& operator-=(A1&, A2); |  |

For every pair I1 and I2, where I1 is an integral type (optionally volatile-qualified) and I2 is a promoted integral type, the following function signatures participate in overload resolution:

I1& operator%=(I1&, I2); |  |
I1& operator<<=(I1&, I2); |  |
I1& operator>>=(I1&, I2); |  |
I1& operator&=(I1&, I2); |  |
I1& operator^=(I1&, I2); |  |
I1& operator|=(I1&, I2); |  |

For every optionally cv-qualified object type `T`, the following function signatures participate in overload resolution:

T*& operator+=(T*&, std::ptrdiff_t); |  |
T*& operator-=(T*&, std::ptrdiff_t); |  |
T*volatile & operator+=(T*volatile &, std::ptrdiff_t); |  |
T*volatile & operator-=(T*volatile &, std::ptrdiff_t); |  |

The behavior of every builtin compound-assignment expression E1 op= E2 (where E1 is a modifiable lvalue expression and E2 is an rvalue expression or a braced-init-list (since C++11)) is exactly the same as the behavior of the expression E1 = E1 op E2, except that the expression `E1` is evaluated only once and that it behaves as a single operation with respect to indeterminately-sequenced function calls (e.g. in f(a += b, g()), the += is either not started at all or is completed as seen from inside g()).

### Example

| This section is incomplete Reason: no example

### See also

Operator precedence

Operator overloading

Common operators
assignment | increment decrement | arithmetic | logical | comparison | member access | other
a = b a += b a -= b a *= b a /= b a %= b a &= b a |= b a ^= b a <<= b a >>= b | ++a --a a++ a-- | +a -a a + b a - b a * b a / b a % b ~a a & b a | b a ^ b a << b a >> b | !a a && b a || b | a == b a != b a < b a > b a <= b a >= b | a[b] *a &a a->b a.b a->*b a.*b | a(...) a, b ? :
Special operators

`static_cast` converts one type to another related type
`dynamic_cast` converts within inheritance hierarchies
`const_cast` adds or removes cv qualifiers
`reinterpret_cast` converts type to unrelated type
C-style cast converts one type to another by a mix of `static_cast`, `const_cast`, and `reinterpret_cast`
`new` creates objects with dynamic storage duration
`delete` destructs objects previously created by the new expression and releases obtained memory area
`sizeof` queries the size of a type
`sizeof...` queries the size of a parameter pack (since C++11)
`typeid` queries the type information of a type
`noexcept` checks if an expression can throw an exception (since C++11)
`alignof` queries alignment requirements of a type (since C++11)

Retrieved from "http://en.cppreference.com/mwiki/index.php?title=cpp/language/operator_assignment&oldid=82582"
Category:

- Todo no example