# std::random_shuffle, std::shuffle

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< cpp‎ | algorithm

Defined in header `<algorithm>` |  |
template< class RandomIt > void random_shuffle( RandomIt first, RandomIt last ); | (1) | (until C++17) (deprecated in C++14)
| (2) |
template< class RandomIt, class RandomFunc > void random_shuffle( RandomIt first, RandomIt last, RandomFunc& r ); |  | (until C++11)
template< class RandomIt, class RandomFunc > void random_shuffle( RandomIt first, RandomIt last, RandomFunc&& r ); |  | (since C++11) (until C++17) (deprecated in C++14)
template< class RandomIt, class URBG > void shuffle( RandomIt first, RandomIt last, URBG&& g ); | (3) | (since C++11)

Reorders the elements in the given range `[first, last)` such that each possible permutation of those elements has equal probability of appearance.

1) The random number generator is implementation-defined, but the function std::rand is often used.
2) The random number generator is the function object `r`.
3) The random number generator is the function object `g`.

### Parameters

first, last | - | the range of elements to shuffle randomly
r | - | function object returning a randomly chosen value of type convertible to std::iterator_traits<RandomIt>::difference_type in the interval [0,n) if invoked as `r(n)`
g | - | a `UniformRandomBitGenerator` whose result type is convertible to std::iterator_traits<RandomIt>::difference_type
Type requirements
- `RandomIt` must meet the requirements of `ValueSwappable` and `RandomAccessIterator`.
- `std::remove_reference_t<URBG>` must meet the requirements of `UniformRandomBitGenerator`.

### Return value

(none)

### Complexity

Linear in the distance between `first` and `last`

### Possible implementation

First version

    template< class RandomIt >
    void random_shuffle( RandomIt first, RandomIt last )
    {
        typename std::iterator_traits<RandomIt>::difference_type i, n;
        n = last - first;
        for (i = n-1; i > 0; --i) {
            using std::swap;
            swap(first[i], first[std::rand() % (i+1)]);
            // rand() % (i+1) isn't actually correct, because the generated number
            // is not uniformly distributed for most values of i. A correct implementation
            // will need to essentially reimplement C++11 std::uniform_int_distribution,
            // which is beyond the scope of this example.
        }
    }

Second version

    template<class RandomIt, class RandomFunc>
    void random_shuffle(RandomIt first, RandomIt last, RandomFunc&& r)
    {
        typename std::iterator_traits<RandomIt>::difference_type i, n;
        n = last - first;
        for (i = n-1; i > 0; --i) {
            using std::swap;
            swap(first[i], first[r(i+1)]);
        }
    }

Third version

    template<class RandomIt, class UniformRandomBitGenerator>
    void shuffle(RandomIt first, RandomIt last,
                 UniformRandomBitGenerator&& g)
    {
        typedef typename std::iterator_traits<RandomIt>::difference_type diff_t;
        typedef std::uniform_int_distribution<diff_t> distr_t;
        typedef typename distr_t::param_type param_t;

        distr_t D;
        diff_t n = last - first;
        for (diff_t i = n-1; i > 0; --i) {
            using std::swap;
            swap(first[i], first[D(g, param_t(0, i))]);
        }
    }

### Example

The following code randomly shuffles the integers 1..10:

Run this code

    #include <random>
    #include <algorithm>
    #include <iterator>
    #include <iostream>

    int main()
    {
        std::vector<int> v = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

        std::random_device rd;
        std::mt19937 g(rd());

        std::shuffle(v.begin(), v.end(), g);

        std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " "));
        std::cout << "\n";
    }

Possible output:

    8 6 10 4 2 3 7 1 9 5

### See also

next_permutation | generates the next greater lexicographic permutation of a range of elements (function template)
prev_permutation | generates the next smaller lexicographic permutation of a range of elements (function template)

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